WebJul 14, 2024 · Problem. Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to the multiple of k, that is, sums up to n*k where n is also an integer. Example 1: Input: [23, 2, 4, 6, 7], k=6 Output: True Explanation: Because [2, 4] is a continuous subarray of size 2 … WebDec 16, 2024 · Here is my solution: class Solution { public boolean checkSubarraySum (int [] nums, int k) { int [] leftSums = new int [nums.length]; int sum = 0; for (int i = 0; i < nums.length; i++) { sum +=...
【LeeCode】523.连续的子数组和_51玖拾柒的技术博客_51CTO博客
WebApr 9, 2024 · 【LeeCode】523.连续的子数组和,【题目描述】给你一个整数数组 nums 和一个整数 k ,编写一个函数来判断该数组是否含有同时满足下述条件的连续子数组:子数组大小 至少为2 ,且子数组元素总和为 k 的倍数。如果存在,返回 true ;;否则,返回 false 。 WebMar 10, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. procedural form b-200
c - Check if subarray with sum 0 exists or not - Stack Overflow
WebApr 21, 2024 · class Solution { public boolean checkSubarraySum(int[] nums, int k) { HashMap map = new HashMap<> (); int sum = nums[0] % k; map.put(sum, 0); for(int i = 1; i [2,4,1,0,6] if(sum == 0) return true; if(map.containsKey(sum) && i - map.get(sum) > 1) return true; // [1,3,0,6], 6 if(!map.containsKey(sum)) { map.put(sum, i); } } return false; } } … WebGiven an integer array nums and an integer k, return true if nums has a good subarray or false otherwise.. A good subarray is a subarray where:. its length is at least two, and; … WebWhether it's raining, snowing, sleeting, or hailing, our live precipitation map can help you prepare and stay dry. procedural framework example