WebFeb 6, 2024 · Note that orbital radius is measured from the center of the Earth. We are know the orbital period of the moon is \(T_m = 27.3217\) days and the orbital radius of the moon is \(R_m = 60\times R_e\) where \(R_e\) is the radius of the Earth. Substituting WebMar 25, 2007 · The radius of Earth is 6.40 x 10³ km. The moon is about 3.84 x 10^5 km away from Earth and has a diameter of 3475 km. The Pacific Ocean surface, which can be considered a convex mirror, forms a virtual image of the moon.

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Web238,855 miles 384,400 kilometers. Orbit and Rotation Period: 27.32 Earth Days. Equatorial Radius: 1,079.6 miles 1,737.5 kilometers. Mass: 0.0123 of Earth's (a bit more than 1 … Web1) The radius of the moon is 1.74 x 10 6 m. The mass of the moon is 7.35 x 10 22 kg. Find the acceleration due to gravity on the surface of the moon. Answer: On the surface of the moon, the distance to the center of mass is the same as the radius: r = 1.74 x 10 6 m = 1 740 000 m. The acceleration due to gravity on the surface of the moon can be ... lada russian car drift game

Acceleration Due to Gravity Formula - Softschools.com

Web"The radius of the moon is 1738 km, whereas the radius of Earth is 6371 km; thus the moon is relatively large in relation to its parent planet." 3.48 × 10 6 m: Moore, Patrick. The Moon. Mitchell Beazley Publishers, 1981. 6. 22 kg, as compared with a figure roughly 81 times larger for the Earth." WebThe period of rotation of Moon in hours is 655.7 hr. Given that Moon has a radius of 1.7 X 10^6 m at its equator, what is the linear velocity (in m/s) at Moon's surface? (Enter the magnitude of the linear velocity at the equator.) WebWe know, Radius of this circle is 3.84 x 10 10 cm. So, distance of the moon from the earth, d = 3.84 x 10 10 cm = 3.84 x 10 8 m. We know, mass of the earth, M 1 = 5.96 x 10 27 g = 5.96 x 10 24 kg Mass of the moon, M 2 = 7.33 x 10 25 g = 7.33 x 10 22 kg So, force acting between the earth and the moon is, F = [Gm 1 m 2 /d 2] la darude